Lecture 2: Binary Representation
Bits review
- 1 byte = 8 bits
Converting between binary and decimal
Example Data representations
| C Data Type | Size (bytes 32bit) | Size (bytes 64bit) | x86-64 |
|---|---|---|---|
char | 1 | 1 | 1 |
short | 2 | 2 | 2 |
int | 4 | 4 | 4 |
long | 4 | 8 | 8 |
float | 4 | 4 | 4 |
double | 8 | 8 | 8 |
long double | - | - | 10/16 |
pointer | 4 | 8 | 8 |
Same size if declared as unsigned
Encoding Integers (w bits)
Unsigned Integers
Example:
Two’s Complement
Example:
Sign Bit
- For 2’s complement, most significant bit is the sign bit
- 0 for positive
- 1 for negative
Numeric Ranges
-
Assume you have a integer type that is 4 bits long
- Unsigned: 0 to 15
- 2’s Complement: -8 to 7
- Unsigned: 0 to 15
-
Unsigned Values:
-
2’s Complement Values
- Other interesting values
Values for different word sizez
| W=8 | W=16 | W=32 | W=64 | |
|---|---|---|---|---|
| TMin | -128 | -32768 | -2147483648 | -9223372036854775808 |
| TMax | 127 | 32767 | 2147483647 | 9223372036854775807 |
| UMin | 0 | 0 | 0 | 0 |
| UMax | 255 | 65535 | 4294967295 | 18446744073709551615 |
C Operators for bitwise operations
Boolean algebra
And
& | 0 | 1 |
|---|---|---|
| 0 | 0 | 0 |
| 1 | 0 | 1 |
Example:
int a = 0b1010;
int b = 0b1100;
int c = a & b; // should return 0b1000Or
| | 0 | 1 |
|---|---|---|
| 0 | 0 | 1 |
| 1 | 1 | 1 |
Example:
int a = 0b1010;
int b = 0b1100;
int c = a | b; // should return 0b1110Xor
^ | 0 | 1 |
|---|---|---|
| 0 | 0 | 1 |
| 1 | 1 | 0 |
Example:
int a = 0b1010;
int b = 0b1100;
int c = a ^ b; // should return 0b0110Not
~ | 0 | 1 |
|---|---|---|
| 1 | 0 |
Example:
int a = 0b1010;
int c = ~a; // should return 0b0101Imagine as set operations
&is intersection|is union^is exclusive or (symmetric difference)~is complement
Logic operators on C
&&is and||is or!is not
Interesting properties:
- View
0asfalseand any non-zero value astrue - Always returns
0or1 - Early termination: if the first operand is
0, the second operand is not evaluated
Example:
int a = 0x69;
int b = 0x55;
int c = a && b; // should return 0x01
int d = a || b; // should return 0x01 (the program will not check b at all since a is non-zero by early termination)
int e = !a; // should return 0x00
int f = !!a; // should return 0x01
int g = !0; // should return 0x01
int *p = NULL;
bool should_access = p && *p; // (avoid null pointer access, returns 0 if p is NULL, otherwise returns true if *p is non-zero)Using bit masks
// goal: compute val mod x and x is a power of 2
unsigned int val = 137; // some value to take mod of
unsigned int x = 16; // x is a power of 2
unsigned int mask = x - 1; // mask is a bit mask that is all 1s except for the least significant bit
unsigned int mod = val & mask; // mod is the result of val mod xShift operations
<<is left shift- Shift bit-vector x left y positions
>>is right shift- Shift bit-vector x right y positions
- Logical shift: fill with 0s
- Arithmetic shift: fill with the sign bit
- Undefined behavior: shift by a number greater than or equal to the word size
Example:
x | 0b01100010 |
|---|---|
x<<3 | 0b00010000 |
Logical shift x>>2 | 0b00011000 |
Arithmetic shift x>>2 | 0b00011000 |
For negative numbers:
x | 0b10100010 |
|---|---|
x<<3 | 0b00010000 |
Logical shift x>>2 | 0b00101000 |
Arithmetic shift x>>2 | 0b11101000 |
Pop count function
- How do you implement a pop count function in a 4-byte memory?
Trivial way:
# define MASK 0x1;
int pop_count(unsigned int x) {
// does not work for negative numbers
int count = 0;
while (x!=0) {
if (x & MASK) count++;
x >>= 1;
}
return count;
}Casting Between Signed and Unsigned Integers in C
Constants
- By default, constants are signed
- To make a constant unsigned, add the
Usuffix
unsigned int a = 0x1234U;Casting
- Explicitly cast to a different type
int tx,ty;
unsigned int ux,uy;
tx = (int) ux;
uy = (unsigned) ty;- Implicit casting also occurs via assignments and procedure calls
tx = ux;
pop_count(tx); // popcount is a built-in function that returns the number of 1s in the binary representation of x (unsigned int)When should I use unsigned integers?
- Don’t use just because the number are non-negative
- Easy to make mistakes
unsigned i;
for (i = cnt-2; i < 0; i++) {
// do something
}If cnt=1 then i will be -1 and the loop will not terminate in short time. LOL.
- Can be very subtle
#define DELTA sizeof(int) // sizeof(int) returns unsigned
int x = 0;
for (int i = CNT; i-DELTA >=0; i-=DELTA) {
// do something
}The expression i-DELTA >= 0 will be evaluated as unsigned and will not terminate.
Code Security Example
You can access the kernel memory region holding non user-accessible data. if you give negative index to the array, it will access the kernel memory region by interpreting the negative index as an unsigned integer.
Change int size
Extension
- When operating with types of different widths, C automatically perform extension
- Converting from smaller to larger type is always safe
- Given w-bit integer
x, - Convert
xtow+kbit integer with the same value
- Given w-bit integer
- Two different types of extension
- zero extension: use for unsigned (similar to logical shift)
- sign extension: use for signed (similar to arithmetic shift)
Truncation
- Task:
- Given w-bit integer
x, - Convert
xtokbit integer with the same value
- Given w-bit integer
- Rule:
- Drop high-order
w-kbits
- Drop high-order
- Effect:
- can change the value of
x - unsigned: mathematical mode on
x - signed: reinterprets the bit (add -2^k to the value)
- can change the value of
Code puzzle
what is the output of the following code?
unsigned short y=0xFFFF;
int x = y;
printf("%x", x); /* print the value of x as a hexadecimal number */The output is 0x0000FFFF it will try to preserve the value of y by sign extending the value of y to x.